3/x^2+x-(-4/x)=1/x+1

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Solution for 3/x^2+x-(-4/x)=1/x+1 equation: 



3/x^2+x-(-4/x)=1/x+1

We move all terms to the left:

3/x^2+x-(-4/x)-(1/x+1)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x+1)!=0

x∈R



We add all the numbers together, and all the variables

x+3/x^2-(-4/x)-(1/x+1)=0

We get rid of parentheses

x+3/x^2+4/x-1/x-1=0

We calculate fractions

We do not support expression: x^3

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